x^2+1x+3x+3=x^2-x

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Solution for x^2+1x+3x+3=x^2-x equation:


Simplifying
x2 + 1x + 3x + 3 = x2 + -1x

Reorder the terms:
3 + 1x + 3x + x2 = x2 + -1x

Combine like terms: 1x + 3x = 4x
3 + 4x + x2 = x2 + -1x

Reorder the terms:
3 + 4x + x2 = -1x + x2

Add '-1x2' to each side of the equation.
3 + 4x + x2 + -1x2 = -1x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
3 + 4x + 0 = -1x + x2 + -1x2
3 + 4x = -1x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
3 + 4x = -1x + 0
3 + 4x = -1x

Solving
3 + 4x = -1x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add 'x' to each side of the equation.
3 + 4x + x = -1x + x

Combine like terms: 4x + x = 5x
3 + 5x = -1x + x

Combine like terms: -1x + x = 0
3 + 5x = 0

Add '-3' to each side of the equation.
3 + -3 + 5x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 5x = 0 + -3
5x = 0 + -3

Combine like terms: 0 + -3 = -3
5x = -3

Divide each side by '5'.
x = -0.6

Simplifying
x = -0.6

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